a bus starts from Delhi to Jaipur at 8 am which is 250 km away .the bus travelled first 100 km in 2 h next 50 km in 30 minutes and next 100 km in next 2 hours . Find the average speed
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Avg speed = (speed1+speed2)/2
speed1= 250/2
= 125 m/s
speed2= 250/2
= 125 m/s
avg speed=( 125+125)/2
= 125 m/s
avg velocity =0 because the displacement is 0 as the bus came back to Delhi covering the same distance
Hope It helps you
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speed1= 250/2
= 125 m/s
speed2= 250/2
= 125 m/s
avg speed=( 125+125)/2
= 125 m/s
avg velocity =0 because the displacement is 0 as the bus came back to Delhi covering the same distance
Hope It helps you
Mark me as brainliest
muskan050:
your answer should be in km/hr because the value of distance and Time is given in km and hour
its wrong
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hope it will help you
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Thanks for your help
my pleasure
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