A bus starts with full of passengers. At first station,it drops 1 by 3 of the passengers and take 1 by 7 at the begining. At the second stop it drops of the new total. At the third an it drops remaining. ( bus capacity = 42 )
Q. 1 How many passengers it takes at first station
Q.2 How many passengers it downs at second station.
Q. 3 How many passengers it drops at last.
Answers
Step-by-step explanation:
it drops 14 passengers at first station
it drops 6 passengers at second station
it drops 22 passengers at third station
The number of passengers dropped at stations 1, 2, and 3 are 14, 4, and 24 respectively.
Given:
At the first station bus drops (1/3) passengers. (1/7) of the passengers.
At the second station bus drops (1/7) of the remaining passengers.
At the third station, the bus drops the remaining number of passengers.
Bus Capacity = 42
To Find:
Passengers it drops at the first station, second station, and third station.
Solution:
According to the question,
Total passengers on the bus = 42
(1/3) of 42 were dropped at station 1. Therefore,
Number of passengers dropped at station 1 =
Total passengers left
Number of passengers dropped at station 2 =
Total passengers left =
Number of passengers dropped at station 3 = 24
Hence, the number of passengers dropped at stations 1, 2, and 3 are 14, 4, and 24 respectively.
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