Question

a bus travelling with velocity 10/s came to rest in 2s it have acceleration or retardation find it​

Answer 1

Answer:

It will have Retardation of 5m/s^2

Explanation:

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Answer 2

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$- 5m \div {s}^{2}$

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Acceleration is defined as the rate of change of velocity.

Final velocity - Initial velocity/ time.

Now, Retardation is defined as negative acceleration.

Means acceleration of a body in opposite direction of its motion is defined as retardation.

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Now it is given bus is moving with a velocity of 10m/s, thus

Initial velocity = 10m/s

Since the bus comes to rest, thus

Final velocity = 0m/s

It is given that bus comes to rest in time

T = 2s.

When a body increases speed it means it accelerated.

But when a body decrease speed it means it retardated. Retardation is represented by (-) sign.

Now for this bus as it comes to rest we say it retardated.

Retardation = v- u/t

Where (v) and (u) are final and Initial velocities respectively.

Retardation =

$0 - 10 \div 2$

$= - 5m \div {s}^{2}$

Here (-) represents retardation.

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