Question

(a)Calculate the number of molecules of SO2 present in 44g of it. (b)If one mole of oxygen atoms weigh 16 grams find the mass of one atom of oxygen (in grams). Urgent i had test tomorrow

Answer 1

1 .

Molar mass of SO2 = 64g
Given mass of SO2 = 44g

no. of moles in 44g SO2 = 44/64 = 0.6875

1 mole = 6.022 * 10²³ molecules

0.6875 mole = 6.022 * 10²³ *0.6875 molecules

0.6865 mole = 4.140125 * 10²³ molecules

or we can say that 44g of SO2 has 4.14 * 10²³ molecules.

2.

1 mole O = 16g

1 mole = 6.022 * 10²³ atoms

6.022 * 10²³ atoms of O = 16g

1 atom of O is 16/ 6.022 * 10²³ gram

1 atom of O is 2.65/10²³ gram

Answer 2

Answer:

1

Molar mass of SO2 = 64g

Given mass of SO2 = 44g

no. of moles in 44g of SO2 = 44/64 = 0.6875

1 mole = 6.022 * 10²³ molecules

0.6875 mole = 6.022 * 10²³ *0.6875 molecules

0.6865 mole = 4.140125 * 10²³ molecules

or we can say that 44g of SO2 has 4.14 * 10²³ molecules.

2.

1 mole of oxygen (O) = 16g

1 mole = 6.022 * 10²³ atoms

6.022 * 10²³ atoms of O = 16g

1 atom of O is 16/ 6.022 * 10²³ gram

1 atom of O is 2.65/10²³ gram