A calorie is a unit of heat or energy and heat equals about 4.2 J where 1 J = 1 Kg m² s⁻². Suppose we employ a system of units in which the unit of mass equals to a kg, the unit of length equals to b m and the unit of time is g s.Show that a calorie has a magnitude 4.2 a⁻¹ b⁻² G² in terms of the new units.
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Answered by
23
Hii dear,
# Proof-
Presently,
1 cal = 4.2 J = 4.2 kg.m^2/s^2 ...(1)
Suppose in new system fundamental units be Kg', m' and s' for mass, length and time respectively.
Kg' = a Kg Hence, Kg = Kg'/a
m' = b m Hence, m = m'/b
s' = g s Hence, s = s'/g
Putting these values in eqn (1)
1 cal = 4.2 (Kg'/a).(m'/b)^2.(s'/g)^-2
1 cal = 4.2 a^-1.b^-2.g^2 Kg'.m'^2.s'^-2
Hope this is helpful.
# Proof-
Presently,
1 cal = 4.2 J = 4.2 kg.m^2/s^2 ...(1)
Suppose in new system fundamental units be Kg', m' and s' for mass, length and time respectively.
Kg' = a Kg Hence, Kg = Kg'/a
m' = b m Hence, m = m'/b
s' = g s Hence, s = s'/g
Putting these values in eqn (1)
1 cal = 4.2 (Kg'/a).(m'/b)^2.(s'/g)^-2
1 cal = 4.2 a^-1.b^-2.g^2 Kg'.m'^2.s'^-2
Hope this is helpful.
Answered by
16
Answer:
Given that,
1 Calorie=4.2 J = 4.2 Kg m2 s-2 ...... (i)
As new unit of mass = α Kg
∴ 1 Kg = 1/α new unit of mass
Similarly, 1 m = β-1 new unit of length
1 s = γ-1 new unit of time
Putting these values in (i), we get
1 calorie = 4.2 (α-1 new unit of mass) (β-1 new unit of length)2 (γ-1 new unit of time)-2
= 4.2 α-1 β-2 γ2 new unit of energy
(Proved)
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