A can 6 times the actual work in 36 days while B can do one-fourth of the original work in 3 days in how many days will both workingtoghther complete the 3 times of the original work
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your answer is in nine days
pankajydv01299:
No bhai
(A) 6 (B) 10 (C) 12 (D) 15
but how whrere is your solution plese show
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Answer:
12 days
Step-by-step explanation:
Let total work be 1
A can do work of 6 in 36 days
Work done by A in 1 day = 6/36 = 1/6
B can do work of 1/4 in 3 days
Work done by B in 1 day = (1/4)*1/3 = 1/12
Work done by A and B in 1 day = 1/6 + 1/12 = 1/4
=> A and B can do the original work in 4 days
=> A and Bcan do 3 times of the original work in 3×4 = 12 days
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