Question

A can do a piece of work in 10 days and B can do the same work in 12 days. How long will they take to finish the work, of 60th work together?​

Answer 1

Step-by-step explanation:

Given A can do the work in 10 days ,B can do the work in 12 days and C can do the work in 15 days.

Then A's one day's work =101

          B's one day's work =121

          C's one day's work =151

Then (A+B +C)'s one day's work =101+121+151=1800450=41

(A+B+C)'s  two days' work =41×2=21

But B leaves 3 days before the work gets finished, so C does the remaining  work alone

C's 3  days' work =151×3=51

Then work done in 2+3 days =21+51=107

Work done by B+C together  =1−107=103

(B + C)'s one day work =121+151=203

So number of days worked by B and C together=

=103×320=2 days

Then total work done =2+3+2=7 days