a can do a piece of work in 10 days nd b can in 20 days. they began together but a leaves 2 days before the completion of work.the whole work will be done in ??
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1 day work of a =1÷10
1 day work of b=1÷20
(A+B)'s 1 day work= 1÷10+1÷20=3÷20
In those 2 day B will do-
2×1÷20=1÷10
remain work=9÷20
=9÷10×20÷3
=6 days
Now, add 2 days that b work alone-
6+2=8 days(answer)
1 day work of b=1÷20
(A+B)'s 1 day work= 1÷10+1÷20=3÷20
In those 2 day B will do-
2×1÷20=1÷10
remain work=9÷20
=9÷10×20÷3
=6 days
Now, add 2 days that b work alone-
6+2=8 days(answer)
studyplaner:
ohhh thats great
im sending one more question try to solve
okk
solve it my frd
posted 2 questions
4 men or 6 women or 10 children can paint house in 5 days. the painting is given to a couple nd their 5 sons. they finish the job in ????
seee this question
nd solve
okkk
okk...let me try..
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