Math, asked by papan96, 10 months ago

A can do a piece of work in 12 days while B can do it in 8 days with the help of C, they finish the work in 4 days then C alone and do the work in? ​

Answers

Answered by babitajain0251
3

Answer:

Step-by-step explanation:A's 1 day work = 1/12

B's 1 day work= 1/8

(A+B+C)'s 1 day work = 1/4

(A+B)'S 1 day work = 1/12 +1/8

=5/24

(A+B+C)- (A+B) = C 's 1 day work

1/4 - 5/24

= 1/24 = C's 1 day work

C can alone do the work in 24 days  

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