Question

A can do a piece of work in 20 days while B can do it in 15 days. With the help of C they finish the work in 1 days. In what time would C alone do it?​

Answer 1

Total work = LCM of 20 and 15 = 60

One day work of A = 60/20 = 3

One day work of B = 60/15 = 4

If one day work of C = x, then

According to the question :

$\frac{60}{3 + 4 + x} = 1 \\ \\ = > 3 + 4 + x = 60 \\ \\ = > x = 53$

One day work of C = 53

C will complete the total work in = 60/53 days

Your question is absolutely wrong so check it once again but according to your question answer is 60/53 days.

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