Question

The sum of the preesnt ages of Tahir and Masud is 18 years.Three years ago Tahir was three times as old as Masud.Find their persent ages

Answer 1

Answer:9

Step-by-step explanation:

T+M = 18; T = 18-M

T-3 = 3(M-3)

T-3 = 3M-9

18-M-3 = 3M-9

15-M = 3M-9

-4M = -24 divide both sides by -4, and remember -/- = +

M = 6

Now solve for T:

T-3 = 3*(6-3)

T-3 = 9

T = 12

------------------------

Check:

6+12 = 18 Correct

Note: You can also solve for T:

T+M = 18; T+6 = 18; T = 12

and then check by substituting in

T-3 = 3(M-3); 12-3 = 3(6-3); 9 = 9

Answer 2

Answer:

The present ages of Masud and Tahir are 6 years and 12 years old.

Step-by-step explanation:

Given :

Sum of their present ages = 18 years

3 years ago = Tahir was three times as old as Masud

To find :

Their present ages

Solution :

$\textsf{\underline{\underline{Let the present ages be - }}}$

• Masud as x
• Tahir as (18 - x)

$\rule{300}{1.5}$

$\textsf{\underline{\underline{Ages 3 years ago - }}}$

• Masud as (x - 3)
• Tahir as (18 - x) - 3

$\rule{300}{1.5}$

$\textsf{\underline{\underline{According to the Question - }}}$

3 years ago = Tahir was three times as old as Masud

⇒ (18 - x) - 3 = 3(x - 3)

⇒ 15 - x = 3x - 9

⇒ - x - 3x = - 9 + (- 15)

⇒ - 4x = - 24

⇒ x = 24/4

⇒ x = 6

Masud = 6 years

$\rule{300}{1.5}$

★ Value of (18 - x)

⇒ 18 - 6

⇒ 12

Tahir = 12 years

$\therefore$ The present ages of Masud and Tahir are 6 years and 12 years old.