Question

A can do a piece of work in 40 days and B in 45 days. They work together for 10 days and then B goes are
In how many days will A finish the remaining work?
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Answer 1

A —40

B—45

Here LCM is total work

Hence Lcm (40,45)= (8x5, 9x5)=8x9x5=360

A’s one day work is 360/40=9 unit

B’s one day work is 360/45=8 unit

in 10 days A does 90 unit and B does 80 units

total work completed is 90+80=170

remaining work is 360–170=190units

A’s one day work 9 unit

so for 190 units he need 190/9 days