Question

A can do a piece of work in 6 days and B can do it in 5 days. If they work together, how many days will they take to complete it?

Answer 1

Answer:

Step-by-step explanation:

A's work in a day = $\frac{1}{6}$th of total work

B's work in a day = $\frac{1}{5}$th of total work

A and B together finish   $\frac{1}{5}$+$\frac{1}{6}$ of the work

= $\frac{11}{30}$th part of total work

so they will finish in $\frac{30}{11}$ days

approximately 2.7 days or 3 days

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

As, A can do a peice of work in 6 days.

So,

$\sf{A \: one \: day \: Work = \frac{1}{6}.......(1)}$

Now, B can do a peice of work in 5 days.

So,

$\sf{B \: one \: day \: work = \frac{1}{5} .......(2)}$

$\rule{200}{2}$

Now, we have to find in how many days A and B can complete their work.

So, Adding Equation 1 and 2.

$\sf{→\frac{1}{6} + \frac{1}{5}} \\ \\ \sf{→\frac{5 + 6}{30}} \\ \\ \sf{→\frac{11}{30}}$

Now, we have find ine day work of A and B. So, we will reciprocal to find the days in which work had completed.

$\sf{→\frac{30}{11}} \: \: days}$