Question

A can do a piece of work in 6 hours while B alone can do it in 16 hours. If A, B and C working together can finish it in 8 hours, in how many hours can C alone finis the work?​

Answer 1

Answer:

$\huge\underline\bold\red{Question!!}$

A can do a piece of work in 6 hours while B alone can do it in 16 hours. If A, B and C working together can finish it in 8 hours, in how many hours can C alone finis the work?

$\huge\underline\bold\red{Answer!!}$

$<font color="blue">$We will solve this using the LCM technique

A takes 6 days and

B takes 8 days

So,let the total work be

LCM(6,8)=24units

A---------≻ 6 days =

$4\frac{units}{day}$

B---------≻ 8 days =

$3 \frac{units}{day}$

A+B=

$7\frac{unit}{day}$

THUS TOTAL TIME

=247247

=10301.9538 days

HOPE IT HELPS ❤️

Answer 2

Answer:

We will solve this using the LCM technique

A takes 6 days and

B takes 8 days

So,let the total work be

LCM(6,8)=24units

A---------≻ 6 days =

4\frac{units}{day}4

day

units

B---------≻ 8 days =

3 \frac{units}{day}3

day

units

A+B

Hope it will be helpful ✌️