A can do a piece of work in 80 hours, B in 60 hours and C in 40 hours. They
all begin together, but B leaves the work 10 hours and A 15 hours before the work is
finished. How long did the work last?
Answers
Answered by
4
Answer:
B leaves the work and A also in 10 and 15 hours respectively
total work is A+B+C =80+60+40= 180 hours
it is said to be that A & B leave the work as their sum of leaving work is 10+15=25 hours
according to question we have to subtract 25 from 180
as 180-25=155. so, 155 hours is the long work last .
hopes its help u mark it as a brainlist answer and follow me . also rate this answer .
Similar questions