Question

A can do piece of work in 4 days, b in 12 days and c in 6 days. If a is assisted by both b and c on every third day, the total work can be done in

Answer 1

Answer:

3 days

Step-by-step explanation:

A takes 4 days

B takes 12 days

C takes 6 days

total work = lcm(4,12,6) = 24

efficiency of A = 24/4 = 6

efficiency of B= 24/12= 2

efficiency of C= 24/6= 4

so a is assisted by b and c on every third day

so first 2 days A alone does 6+6=12 work

on 3rd day A,B and C together does 6+2+4=12 work

so total work completed after 3 days = 24

so the total  work will be completed in 3 days