A can do piece of work in 4 days, b in 12 days and c in 6 days. If a is assisted by both b and c on every third day, the total work can be done in
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Answer:
3 days
Step-by-step explanation:
A takes 4 days
B takes 12 days
C takes 6 days
total work = lcm(4,12,6) = 24
efficiency of A = 24/4 = 6
efficiency of B= 24/12= 2
efficiency of C= 24/6= 4
so a is assisted by b and c on every third day
so first 2 days A alone does 6+6=12 work
on 3rd day A,B and C together does 6+2+4=12 work
so total work completed after 3 days = 24
so the total work will be completed in 3 days
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