Question

A candidate scored 25% marks in an examination and failed by 30 marks while another candidate who scored 50% marks got 20 marks more than minimum pass marks. find the maximum marks and minimum pass marks. ​

Answer 1

Step-by-step explanation:

Let the minimum passing mark be x.

Therefore

$25 \% \: of \: x + 30 = x \\ 0.25x + 30 = x \\ 30 = x - 0.25x \\ 30 = 0.75x \\ x = \frac{30}{0.75} = \frac{3000}{75} = 40 \\ hence \: minimum \: passing \: mark \: is \: 40.$

Now,

Let the Maximum passing mark be y.

Therefore,

$50 \% \: of \: y = y-20 \\ 0.5y = y-20 \\ 20 = y - 0.5y\\ 20 = 0.5y \\ y =\frac{20}{0.5} = \frac{200}{5} = 40 \\ hence \: maximum \: passing \: mark \: is \: 40$

Answer 2

minimum pass marks is 48.