Question

A candle of 6.5 cm height is kept at 12 cm in front of a convex mirror of radius of curvature 30 cm. the ratio of size of object to that of magnification produced by mirror is

Answer 1

Explanation:

use mirror formula and magnification formula

Answer 2

Answer:

The ratio of the object's size to that of magnification produced by the mirror is 5.72:6.5.

Explanation:

Given:
Distance between the candle and mirror(u)=12cm

Height of the candle(h)=6.5cm

Radius of curvature(R)=30cm

To find:

The ratio of the size of the object to that of magnification produced by the mirror=?

Solution:
$f=\frac{R}{2}$

∴f=15cm

We know that,

The mirror formula is given by,

$-\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$

∴1/v=1/12+1/15

∴ $\frac{1}{v} =\frac{15+12}{15*12}$

∴v=10.588cm

The magnification is

∴$m=-\frac{v}{u}$

m= -0.88

$m=\frac{h^{1} }{h}$

∴h¹ =0.88*6.5=5.72

Therefore, the ratio of the size of the object to that of magnification produced by the mirror is 5.72:6.5.