Question

A cantilever beam of cross-section 90 mm. width 120 mm deep carries a UDL of 12 KN/m. over the entire length and a concentrated load of 15 KN at the right end. Find the bending stress in the beam, when the length of beam is 10 m

Answer 1

Answer:

Bending Stress: 3472.22 MPa

Explanation:

Bending stress= $\frac{6M}{bh^{2} }$

Shear Force= 12×10+15=135 KN

Moment, M=(135+15)×0.5×10=750 KN.m ( SFD:  area of Trapezium)

Bending Stress= $\frac{6*750}{0.09*0.12^{2} }$ = 3472.22 MPa