Question

A capacitor of capacitance C is charged to Vo potential. The positive plate of this capacitor is now connected to the negative terminal of Vo potential difference battery and vice versa. Calculate the heat developed in the connecting wires.

Answer 1

Heat developed in the connecting wires is = 1/2 C(2E)² = 2CE²

Explanation:

• Initial voltage of capacitor "V" = -E
• Voltage of capacitor at steady state,  = E
• At steady state charge doesn't flow from circuit to capacitor because both are in same potential.  

Now, heat developed in connected wire = 1/2 CV²

Here C is capacity of capacitance and V is change in voltage.

So:

V = E - (-E) = 2EV =

V = 1/2 C(2E)² = 2CE²

Hence, heat developed in the connecting wires is = 1/2 C(2E)² = 2CE²

Also learn more

A capacitor is connected to a 12 V battery through a resistance of 10 Ohm. It is found that the potential difference across the capacitor rises to 4.V in 1 micro seconds . Find the capacitance of the capacitor.?

https://brainly.in/question/5416023

Answer 2

Answer:

Q= CVo

work done = 2Q (vo)

= 2CVoVo

=2CVo²

work done = heat developed

heat developed in the wires is 2CVo²