Question

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If altitude and base of each tile is 10cm and 4cm respectively, find the cost of polishing the design at the rate of ₹9.50per dm^2​

Answer 1

Answer:

Given that length of the tile = 10cm = 1dm.

Given that Base of the tile = 4cm = 0.4dm.

We know that Area = l * b

                                 = 1 * 0.4

                                 = 0.4dm^2.

Given that total number of tiles in the room = 1000.

Therefore the total area of the floor = 1000 * 0.4

                                                             = 400

Given that cost of polishing per dm^2 = 9.50dm.

Therefore the cost of polishing = 400 * 9.50

=3800

Hope it helps you.

                                                   

Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\green{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\bf{Given\::}}}}$

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If the altitude and base of each tile is 10cm and 4cm respectively.

$\bf{\Large{\underline{\bf{To\:find\::}}}}$

The cost of polishing the design at the rate of ₹9.50/dm².

$\bf{\Large{\underline{\bf{\blue{Explanation\::}}}}}$

We know that,

$\bf{\boxed{\bf{1cm=0.1dm}}}}$

$\bf{We\:have\begin{cases}\sf{The\:length\:of\:the\:tile=10cm=1dm}\\ \sf{The\:breadth\:of\:the\:tile=4cm=0.4dm}\end{cases}}$

__________________________________________________________

We know that area of parallelogram:

→ (Base × Altitude)    [sq.units]

→ (0.4 × 1)dm²

→ 0.4dm²

→ The total number of tiles consists of room = 1000 tiles.

∴ Total area of the floor = (1000 × 0.4)dm²

→ Total area of the floor = 400dm²

__________________________________________________________

The cost of polishing the design at the rate of ₹9.50/dm².

The cost of polishing the design at the rate = ₹(400 × 9.50)

∴ The cost of polishing the design at the rate is ₹3800.