Question

A car accelerate uniformly from 18kmh-1 to 36kmh-1 in 5 sec. Calculate the acceleration and the distance by the car in that time

Answer 1

u=18Km/s

=18*1000/3600

=5m/s

v=36Km/s

=36*1000/3600

=10m/s

t=5secs

a=v-u/t

=10-5/5

=1m/s^2

v^2=u^2+2as

100=25+2*1*s

s=75/2

=37.5m