Question

A car accelerates from rest at a constant rate for t second and covers a distane x the distance covered by it in next t second will be

Answer 1

Acceleration in t sec,


a=x/t




Acceleration in next t second it moves another x distance
=>x+x=2x
. . y+y=2y


a=2x/2y


a=x/y



. IT IS A LINEAR ACCELERATION, moves equal distance in equal time.





SO THE DISTANCE TRAVELED IN NEXT x sec IS 2x meter.