Question

A car accelerates uniformly from 20 km/h to 35km/h I 5 seconds .
i] Calculate the acceleration.
ii] The distance covered by that time

Answer 1

20 km/hr=20*5/18=5.5m/s.
35 km/hr=35*5/18=9.7m/s.
time =5 seconds.
acceleration= v-u/t
acceleration =9.7-5.5/5
acceleration=0.84m/s2
distance= ut+1/2at2
distance=20*5+1/2*0.84*25
distance =100+1/2*21
distance=100+10.5
distance covered=110.5m.
hope it helps plz mark my answer brainlist answer

Answer 2

$\huge{\boxed{\sf{Answer}}}$

What is Acceleration...???

• Change in the velocity of an object per unit time.

• Acceleration a = v-u/t

• S.I Unit : m/s²

Here, u = initial velocity and v = final velocity.

          a = acceleration and t = time.

i) u = 20 km/h = 5.5 m/s

  v = 35 km/h = 9.7.. m/s

  t  =  5 second

  a = v-u/t

  a = 9.7 - 5.5 / 5

  a = 4.2 / 5

  a = 0.84 m/s²

ii) The Distance covered :

    s = ut + 1/2 at²

    Here, s = distance travelled by the object.

          t = time

          a = uniform acceleration.

          s = 5.5 × 5 + 1/2 ( 0.84 ) ( 5 )²

          s = 27.5 + 1/2 × 0.84 × 25

          s = 27.5 + 10.5

          s =  38m.

Hence, i will conclude here with final answers :

Ans i) :  Acceleration = 0.84 m/s²

and ii) : s =  38m.