A car at rest attains a velocity of 10 m/s in 25 s. Then he applies brake such that he again comes to rest after next 50 s. Calculate acceleration of car in both cases. Also find total distance covered by car
Answers
Answered by
2
case 1
V=10m/s
u=0m/s
t=25s
a=10/25
= 0.4m/s^2
case 2
u=10 m/s
v=0m/s
t=50s
a= -10/50
=-0.2m/s^2
......hope it helps
V=10m/s
u=0m/s
t=25s
a=10/25
= 0.4m/s^2
case 2
u=10 m/s
v=0m/s
t=50s
a= -10/50
=-0.2m/s^2
......hope it helps
Similar questions