A Car gave a reading of distance 2000 km at the start of a trip and 2288 at the end of the trip . If the trip took 8 hrs ,calculate the average speed of the car in m/s?
Answers
Answered by
1
average speed=total distance travelled / total time
here total distance will be 288km
time taken=8hours
=>288/8
=36 km/h
=10m/s
2) first 30 km => v = s / t
30 = 30 / t =>t = 1 hr
next 70 km
let velocity be x
v = s / t =>x = 70 /t
t = 70 / x
total time taken i=> 1 + 70/ x = (70 + x) / x
dist. travelled is 100km
avg. velovity = total dist / total time
40 = 100|(70 + x) / x => 40. (70+x) / x = 100
2800 + 40x - 100x = 0 => - 60x = - 2800 => x = - 2800 / -60
x = 45.55 km/hr
here total distance will be 288km
time taken=8hours
=>288/8
=36 km/h
=10m/s
2) first 30 km => v = s / t
30 = 30 / t =>t = 1 hr
next 70 km
let velocity be x
v = s / t =>x = 70 /t
t = 70 / x
total time taken i=> 1 + 70/ x = (70 + x) / x
dist. travelled is 100km
avg. velovity = total dist / total time
40 = 100|(70 + x) / x => 40. (70+x) / x = 100
2800 + 40x - 100x = 0 => - 60x = - 2800 => x = - 2800 / -60
x = 45.55 km/hr
Answered by
4
Answer:
average speed=total distance travelled / total time
here total distance will be 288km
time taken=8hours
=>288/8
=36 km/h
=10m/s
2) first 30 km => v = s / t
30 = 30 / t =>t = 1 hr
next 70 km
let velocity be x
v = s / t =>x = 70 /t
t = 70 / x
total time taken i=> 1 + 70/ x = (70 + x) / x
dist. travelled is 100km
avg. velovity = total dist / total time
40 = 100|(70 + x) / x => 40. (70+x) / x = 100
2800 + 40x - 100x = 0 => - 60x = - 2800 => x = - 2800 / -60
x = 45.55 km/hr
hope this helps u dear ❤️
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