Question

A car increases its velociy from 18km/h to 36km/h in 5sec at a constant accelaration .find the distance







.

Answer 1

Answer:-

s = 37.5m

Given :-

u = 18 km/hr

v = 36 km/hr

t = 5s

To find :-

The distance travelled by car.

Solution:-

First convert the velocity in m/s by multiply with 5/18.

u = 18 × 5/18

u = 5 m/s

v = 36 × 5/18

v = 2 × 5

v = 10 m/s

Now, We have to find acceleration,

$\huge \boxed{a = \dfrac{v-u}{t}}$

→$a = \dfrac{10 -5}{5}$

→$a = \dfrac{5}{5}$

→$a = 1m/s^2$

Distance travelled by car is given by :-

$\huge \boxed{2as = v^2 - u^2}$

→$2\times 1 \times s = (10)^2 - (5)^2$

→$2 \times s = 100 - 25$

→$2s = 75$

→$s = \dfrac{75}{2}$

→$s = 37.5 m$

hence,

The distance travelled by car is 37.5 m.