Question

a car initially starts moving with a constant acceleration of 10 ms-1 and travels a distance of 50m find its final velocity and time taken.​

Answer 1

Answer:

brow your answers is :

5ms_1

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Final\:velocity=10}\sqrt{10}\:m/s}}$

$\green{\therefore{\text{Time\:taken=3.16\:sec}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a car initially starts moving with a constant acceleration of 10 ms^2 and travels a distance of 50m.

• We have to find Final velocity of car and time taken to reach 50 m distance.

$\green{\underline\bold{Given :}} \\ :\implies \text{Initial\:velocity(u)=0 m/s} \\ \\ :\implies \text{Acceleration(a)= 10\:m/s}^{2} \\ \\ :\implies \text{Distance(s)= 50\:m} \\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Final\:velocity= ?}\\\\ :\implies Time\:taken=?$

• According to given question :

$\bold{Using \: Third\: equation \: of \: motion : } \\ : \implies v^{2} = u^{2} + 2as\\ \\ : \implies v^{2}= 0 + 2\times 10\times 50 \\ \\ : \implies v^{2}= 1000 \\\\ : \implies v= \sqrt{1000} \\ \\ \green{ :\implies \text{v= 10}\sqrt{10} \: m/s}$

$\bold{Using \: First\: equation \: of \: motion : } \\ : \implies v = u + at\\ \\ : \implies 10\sqrt{10}= 0 + 10\times t \\ \\ : \implies t=\frac{10\sqrt{10}}{10}\\\\ : \implies t= \sqrt{10}\\ \\ \green{ :\implies{\text{t= 3.16\:sec}}}$