A car is intended to move on a rough road by applying a force of 1000N. cal force of friction if the car starts moving with constant velocity of 30km per h on road
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Answered by
14
the force of friction is same as the force applied by car on road as per Newton's third law of motion action and reaction are equal and opposite
rishabhraj5:
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but here velocity is constant therefore acceleration is zero so situation can be imagine as stationary and not moving.
Answered by
9
Answer:answer is -1000N
Explanation:By Newton's third law of motion
As per the car is moving with constant velocity ,there net force on car is zero
FA =1000N,Fr=?
Hence applied force FA+Frictional force Fr=0
Fr=-1000N (Negative sign shows that ,the Frictional force is opposite to applied force)
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