A car is moving at a speed of 50 km/hr after 2 seconds it is moving at 60 km/hr. Calculate the acceleration of of the car.
Answers
Answer:
To solve this, we first assume that over those two seconds, the car has a constant acceleration. Once you know this, it's a simple job of calculating the change in speed (∆v or ∆s) over the duration (change in time = ∆t). In this situation, you would do (60–50)/(2) = 5 km/s². Now you might want to know the acceleration in the same unit of time as in the speeds, in which case you would take the answer we have just found and multiply it by 3600² (60 minutes in an hour • 60 seconds in a minute, and square everything since the unit of time is squared in the original answer). By doing this, you get (5 km/s²) • (3600² seconds) = 6.48 * 10^7 km/h².
Answer:
Given that:
Initial speed (u) = 50 km/hr
Distance (S) = 6 m = 6/1000 km
Final velocity (v) = 0
use V2 = u2 + 2 a S
0 = 502 + 2 × a × (6/1000)
So a = - (2500 × 1000)/6 m/s2
Now initial speed (u) = 100 km/hr
Final speed (v) = 0
use V2 = u2 + 2 a S
0 = 1002 + 2 × (- (2500 × 1000)/6) S'
So S' = (10000 × 6)/(5000000) = 0.012 km = 12 m