Question

A bicycle moving with a velocity of 5m/s speeds up with an acceleration of 0.5 m/s2. What will be its velocity after 5 sec and how far does it move during this time?

Answer 1

Answer

• Final velocity = 7.5 m/s.
• Distance travelled by the bicycle = 31.25 meters.

Given

• Initial velocity of bicycle = 5 m/s.
• Acceleration = 0.5 m/s².
• Time taken = 5 seconds.

To Find

• Final velocity of the bicycle.
• Distance covered by the bicycle.

Step By Step Explanation

First we need to find the final velocity of the bicycle. So let's do it !!

• Using first equation of motion.
• v = u + at

Substituting the values :

$\longmapsto{\mathfrak{ \red{v = u + at}}} \\ \\ :\implies\sf v = 5 + 0.5 \times 5 \\ \\:\implies\sf v = 5 + 2.5 \\ \\:\implies{\bf{ \green{v = 7.5m/s}}}$

Therefore, final velocity of the bicycle = 7.5 m/s.

Now, we need to find the distance travelled by the car. So let's do it !!

• Using third equation of motion.
• v² - u² = 2as

Substituting the values :

$\longmapsto{ \tt{ \pink{ {v}^{2} - {u}^{2} = 2as}}} \\ \\ :\implies\sf {(7.5)}^{2} - {(5)}^{2} = 2 \times 0.5\times s \\ \\:\implies\sf 56.25 - 25 = 1s \\ \\:\implies\sf 31.25 = 1s \\ \\ :\implies\sf \cfrac{31.25}{1} = s \\ \\:\implies\bf{ \purple{ 31.25 \: meter= s}}$

Therefore, distance travelled by the bicycle = 31.25 meters.

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