A car is moving with a velocity of 16m/s when beakrs are applied. the force applied by the brake is 1000n .the mass of the car alogn with its passengers is 1200kg how long should the brakes be applied
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in this question,
initial velocity is 16 m/s
final velocity is 0 m/s
As you know ,
F=MA (here force is 1000N and mass is 1200kg and decelleration is X )
or, 1000 = 1200* X
or, X =1000/1200
or, X= 0.83333.... m/ s Square
so, using 1st law of motion ,
v=u+at
0= 16 +(- 0.83)* t
or, - 16= -0.83t
or, t= -16/83 *100
or, time=19.6 second.
Answered by
1
Answer:
initial velocity is 16 m/s
final velocity is 0 m/s
As you know ,
F=MA (here force is 1000N and mass is 1200kg and decelleration is X )
or, 1000 = 1200* X
or, X =1000/1200
or, X= 0.83333.... m/ s Square
so, using 1st law of motion ,
v=u+at
0= 16 +(- 0.83)* t
or, - 16= -0.83t
or, t= -16/83 *100
or, time=19.6 second. ........please vote and like
Explanation:
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