Question

A car is moving with speed of 60km/h and car b is moving with a speed of 75 km/h along parallel straight path starting from the same point what is the position of car a w.r.t b after 20 minutesA

Answer 1

Answer: The position of car A w.r.t.B is 4.95 km.

Explanation:

Given that,

Speed of car A$v_{A} = 60km/h$

Speed of car B$v_{B} =75km/h$

Time t = 20 minutes

We know that,

The distance of car A

$d_{A} = vt$

$d_{A} = 60km/h\times 0.33h$

$d_{A} = 19.8 km$

The distance of car B

$d_{B} = 75km/h\times0.33h$

$d_{B} = 24.75 km$

Now, the position of car A w.r.t.B is

$d = d_{B}-d_{A}$

$d = 24.75km-19.8km$

$d =4.95 km$

Hence, the position of car A w.r.t.B is 4.95 km.

Answer 2

"Given that,

Speed of car $A = 60\frac { Km }{ h }$

Speed of car $B = 75\frac { Km }{ h }$

Time t = 20 minutes

We know that,

The distance of car A

$d_A = vt$

$d_A = 60\frac { Km }{ h } \times 0.33h$

$d_A = 19.8 km$

The distance of car B

$d_B = 75\frac { Km }{ h } \times 0.33 h$

$d_B = 24.75 Km$

Now, the position of car A with respect to B is

$d = d_B-d_A$

d = 24.75 -19.8

d = 4.95 km

Hence, the position of car A with respect to B is 4.95 km."