Question

A car is moving with the velocity at a time t is given by (t)= t2+3t , what is its change in position from time t=1 to t=10.

Answer 1

Distance covered, x = Integral of velocity (3t + 4)

= (3/2)*(t^2) + 4t.

So, when t = 2 seconds,

x = (3/2)*4 + 4*2 = 14 m.