A car is stopped at a red light. When the light turns green, the driver accelerates the car at a constant rate of +5.0 m/s2 for 7.0 seconds. The car’s total displacement is? m.
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Answered by
4
v=u+at where v=final velocity, u=initial velocity, a=acceleration, t=time.
Here t=6 seconds, a=+5 m/s2 and u=0 as the car is initially at rest.
Thus v=0+(5)(7)
v=35m
Here t=6 seconds, a=+5 m/s2 and u=0 as the car is initially at rest.
Thus v=0+(5)(7)
v=35m
Arceus11:
sorry this is wrong, internet connection died down so couldn't complete it
Answered by
3
s=ut + 1/2at^2
=0×7.0 + 1/2 ×5×7×7 (u=0 ;as the body was at
rest)
=0+122.5
= 122.5m
so displacement =122.5m
HOPE IT HELPS
THANK YOU.
=0×7.0 + 1/2 ×5×7×7 (u=0 ;as the body was at
rest)
=0+122.5
= 122.5m
so displacement =122.5m
HOPE IT HELPS
THANK YOU.
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