Question

A car is travelling at a speed of 40 m/s and speeds up to 20 m/s in 5 s. Find Acceleration & Distance Travelled

Answer 1

Explanation:

ANSWER:-

• Intial Speed = 40 m/s
• Final Speed = 20 m/s
• Time is 5 seconds

$a = \frac{v - u}{t}$

$a = \frac{40 - 20}{5}$

$a = \frac{20}{5}$

Acceleration is 4 m/s².

v² - u² = 2as

(40)²-(20)²= 2×4×distance

1200 = 8× distance

Distance = 150 meters

Distance is 150 meters.

Things to Note:-

Some SI Units:-

• Distance is measured in meters.
• Speed is measured in meter/seconds
• Time is in seconds.
• Acceleration is measured in metre/second square.
• SI units are applicable except mentioned in the question.
• V is also written AS FINAL Speed
• U is also written AS Initial Speed.
• a is acceleration.
• Remember the formula in the above question.

Answer 2

In this Case

Given

• Initial Speed (u) = 20 m/s
• Final Speed (v) = 40 m/s

To Find

• Acceleration
• Distance Travelled

Calculating Acceleration

Formula Used :- v = u + at

Substituting Values

☞ 40 = 20 + a × 5

☞ 40 - 20 = 5a

☞ 20 = 5a

☞ 5a = 20a

☞ a = 20/5

☞ a = 4

Therefore, we got Acceleration 4 m/s²

Calculating Distance Travelled

Formula Used :- v² - u² = 2as

Substituting Values

☞ (40)² - (20)² = 2 × 4 × s

☞ 1600 - 400 = 8s

☞ 1200 = 8s

☞ 8s = 1200

☞ s = 1200/8

☞ s = 150

Therefore, we got Distance Travelled 150 m

Hence

Acceleration = 4 m/s²

= 4 m/s²Distance Travelled = 150 m