Question

A car moving on a straight road with a speed 120 km/h is brought to stop with in a distance of 200m what is the retardation of the car and h9w long does it takes for car to stop

Answer 1

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Answer 2

Explanation:

Given that,

Initial speed of the car, u = 120 km/h = 33.33 m/s

Finally, it stops v = 0

Distance, d = 200 m

Let a is the retardation of the car. Using third equation of motion as:

$a=\dfrac{v^2-u^2}{2d}$

$a=\dfrac{-(33.33)^2}{2\times 200}$

$a=-2.77\ m/s^2$

The retardation of the car is $-2.77\ m/s^2$.

Let t is the time taken by the car to stop it. Using the first equation of motion as :

v = u + at

$t=\dfrac{-u}{a}$

$t=\dfrac{-33.33}{-2.77}$

t = 12.03 seconds

Hence, this is the required solution.