a car moving with a velocity of 54 km hr is accelerated so that its velocity becomes 72km/hr in 15sec. calculate the acceleration of the car
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Answered by
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HI there !!
Initial velocity = u = 54km/hr = 54 × 5/18 = 15m/s
Final velocity = v = 72 km/hr = 72 × 5/18 =20 m/s
Time = t = 15 sec
Law of motion :
v = u + at
20 = 15+ a × 15
20 = 15 + 15 a
15a + 15 = 20
15a = 20 - 15
15 a = 5
a = 5/15
a = 0.33 m/s²
Initial velocity = u = 54km/hr = 54 × 5/18 = 15m/s
Final velocity = v = 72 km/hr = 72 × 5/18 =20 m/s
Time = t = 15 sec
Law of motion :
v = u + at
20 = 15+ a × 15
20 = 15 + 15 a
15a + 15 = 20
15a = 20 - 15
15 a = 5
a = 5/15
a = 0.33 m/s²
Answered by
1
Initial velocity of the car u = 54 Kmh = 15 m/s
Final velocity v = 72Kmh = 20 m/s.
From the equation, v = u + at
a = v - u /t
= 20 - 15/15
= 5 / 15
= 0.33 m/s².
:)
Final velocity v = 72Kmh = 20 m/s.
From the equation, v = u + at
a = v - u /t
= 20 - 15/15
= 5 / 15
= 0.33 m/s².
:)
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