Question

A car of mass 500 kg is moving with a speed of 36 km per hour. when breaks are applied at a distance of 150m. Calculate the force applied by the breaks of a car and work done before stopping

Answer 1

given:
initial velocity=36km/hr
=10m/s

mass=500kg

distance=150m

Final velocity=0

v²=u²+2as
0²=10²+2.a.150
-100=300a
a=-1/3

force applied=ma
=500*1/3
=500/3N

the work done=FS
=500/3*150
=500*50
=25000J

Answer 2

25000J........................