Question

A car purchased for rupees 38000 is value depreciated at 10% per annum what will be its value after 2 years​

Answer 1

Answer:

Step-by-step explanation:

vgiven,

initial value of scooter=P= rs.56000

rate=R= 10%

time=N=3 years

value=P*1-R100n. = rs.56000*1-101003

⇒rs.56000*100-101003

⇒ rs.56000*901003=rs.56000*9103=rs.56000*910*910*910=rs.56*9*9*9

⇒rs.40824

so,its value after 3 years will be 40824 rs.

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Answer 2

Answer:

Rs 30,780

Step-by-step explanation:

equivalent rate of depreciation

= 10 + 10 - (10 × 10 /100) = 19%

value after 2 yrs

=38000-19% of 38000= Rs 30780