A car stars from rest and moves with a constant acceleration of 0.2 m/s² . What will be its speed after 2 min? What will be the distance covered by the car during this period
Answers
Answer:
speed=12 metre/second and distance=1440m
Explanation:
Given, initial velocity=0 metre
accleration=0.2metre/second
time=2 minutes or 120 seconds
to find:-speed and distance
according to the second equation of motion
distance=ut+1/2at^2
distance=0*120+1/2*0.2*(120)^2
distance=0+1/2*2/10*14400
distance=1440metre
distance=speed*time
speed=distance/time
speed=1440/120
speed=12 metre/second
Speed of Car is 12 m/s.
Distance covered is 1440 m.
Given Terms:
- A car starts from rest.
- Acceleration produced by car is 0.2 m/s².
- Time taken is 2 minutes.
Need To Find:
- What is the distance covered by car ?
Solution: Assuming distance covered by car as S.
We can calculate distance covered by using third equation of motion that is S = ut + 1/2at²
➥ s = ut + 1/2at²
- Car has started from rest so initial velocity of car will be 0 metre per second.
- Time in seconds = 2 × 60 = 120
➥ s = 0 × 120 + 1/2 × 2/10 × 120 × 120
➥ s = 0 + 1/10 × 14400
➥ s = 1440 metre
Required distance covered is 1440 metre .
To calculate speed we'll use formula :
➥ speed = distance/time
.
➥ 1440/120
➥ 12 metre per second
Therefore required speed of car is 12 m/s.