A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find
(i) the acceleration
(ii) distance travelled by car assume motion of car is uniform?
Answers
Answered by
13
A=V-U/t
=54-0/2
=54/2
=27 m/s^2
S=ut+at^2/2.
=at^2/2
=27×4/2
=54m
please let me know about the answer. if you like the answer then give me the brainliest answer.
=54-0/2
=54/2
=27 m/s^2
S=ut+at^2/2.
=at^2/2
=27×4/2
=54m
please let me know about the answer. if you like the answer then give me the brainliest answer.
Answered by
11
for acceleration
a= v -u/t
a= 54 -0/2
2
a= 27 m/s
for distance
s = ut + 1/2 at×t
s= 0 × 2 + 1/2 × 27×2×2
s= 0 + 1/2 × 108
s = 2+1/2 × 108
s= 3/2 × 108
s= 162 m
a= v -u/t
a= 54 -0/2
2
a= 27 m/s
for distance
s = ut + 1/2 at×t
s= 0 × 2 + 1/2 × 27×2×2
s= 0 + 1/2 × 108
s = 2+1/2 × 108
s= 3/2 × 108
s= 162 m
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