Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped.

Answer 1

Answer:

u = 0

a = 10m/s²

t = 5s

Formula =>   v = u + at

                     v = 0 + (10 × 5 )

                     v = 0 + 50

                     v = 50m/s

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Answer 2

FINAL VELOCITY IS 50 m/s

Given:

• Acceleration is 10 m/s²
• Time is 5 seconds.

To find:

• Final velocity after drop ?

Calculation:

Since the object was dropped, the initial velocity (u) will be zero.

Applying 1st EQUATION OF KINEMATICS:

$v = u + at$

$\implies \: v = u + gt$

$\implies \: v = 0 + (10 \times 5)$

$\implies \: v =50 \: m {s}^{ - 1}$

So, final velocity of object is 50 m/s.