a car start from rest with uniform acceleration 2ms^2.calculate velocity and displacement after 10sec.
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Answer:
u=0
a=2m/S
2
t=10Second
S
1
=ut+0.5at
2
s
1
=0+0.5×2×100=100m
S
2
=v+2
v=u+at=0+20=20m/s
s
2
=20×30=600 m
0
2
−v
2
=2(−a)s
3
s
3
=
8
400
=50m
s=s
1
+s
2
+s
3
=100+600+50=750
Explanation:
u=0
a=2m/S
2
t=10Second
S
1
=ut+0.5at
2
s
1
=0+0.5×2×100=100m
S
2
=v+2
v=u+at=0+20=20m/s
s
2
=20×30=600 m
0
2
−v
2
=2(−a)s
3
s
3
=
8
400
=50m
s=s
1
+s
2
+s
3
=100+600+50=750
- therefore answer is 750
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