Question

A car starting from rest accelerates at the rate f through a distance s then continues at constant speed for time t then decelerate at rate f\2 to come to rest. If total distance travelled is 15S then

Answer 1

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '' .S= (ft^2)/72