Science, asked by sarthaknarang, 11 months ago

A car starts from rest and accelerates with 2 metre per second square for 5 seconds then moves with uniform speed for next 5 seconds and then apply brakes and comes in rest in 3 seconds find the total distance travelled​

Answers

Answered by santy2
5

Answer:

A car starts from rest and accelerates with 2 metre per second square for 5 seconds then moves with uniform speed for next 5 seconds and then apply brakes and comes in rest in 3 second.

The total distance travelled​ by this car is 155 metres.

Explanation:

To calculate this question we use the kinematics equations/ equations of linear motions (SUVAT) attached:

First: Calculate the distance travelled using the SUVAT during the acceleration:

Displacement is S

Acceleration, a  is 2m/s²

Initial velocity u = 0 m/s   ......it starts at rest

Time taken , t  = 5 s

S = ut + 1/2at²

S = (0 × 5) + (1/2 × 2 × 5²)

S = 0 + 25

S = 25 m

Therefore the car moves for 25 meters in the first phase.

Second:Calculate the distance travelled in when moving with the uniform velocity

v² = u² + 2as

v² = 0² + (2 × 2 × 25)

v² = 100

v = 10 m/s

The velocity in this phase is 10m/s, use this to find the distance travelled

S = (u+v)t/2

S = 5(20 + 20)/2

S = 200/2

S = 100m

The car moves in this 2nd phase for 100 metres

Third: Calculate the distance travelled during the deceleration

v = 0 m/s ....the car's final velocity is 0 because it stops.

u = 20 m/s   ......the car's initial velocity is 20 m/s

t = 3 s

Calculate the distance travelled

S = t(u+v)/2

S = 3( 20 + 0)/2

S = 60/2

S = 30 meters

The distance travelled is

The total distance travelled is:

25 metres + 100 metres + 30 metres

= 155 metres

Answered by shawdhanraj
0

Answer:

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