A car starts from rest and accelerates with 2 metre per second square for 5 seconds then moves with uniform speed for next 5 seconds and then apply brakes and comes in rest in 3 seconds find the total distance travelled
Answers
Answer:
A car starts from rest and accelerates with 2 metre per second square for 5 seconds then moves with uniform speed for next 5 seconds and then apply brakes and comes in rest in 3 second.
The total distance travelled by this car is 155 metres.
Explanation:
To calculate this question we use the kinematics equations/ equations of linear motions (SUVAT) attached:
First: Calculate the distance travelled using the SUVAT during the acceleration:
Displacement is S
Acceleration, a is 2m/s²
Initial velocity u = 0 m/s ......it starts at rest
Time taken , t = 5 s
S = ut + 1/2at²
S = (0 × 5) + (1/2 × 2 × 5²)
S = 0 + 25
S = 25 m
Therefore the car moves for 25 meters in the first phase.
Second:Calculate the distance travelled in when moving with the uniform velocity
v² = u² + 2as
v² = 0² + (2 × 2 × 25)
v² = 100
v = 10 m/s
The velocity in this phase is 10m/s, use this to find the distance travelled
S = (u+v)t/2
S = 5(20 + 20)/2
S = 200/2
S = 100m
The car moves in this 2nd phase for 100 metres
Third: Calculate the distance travelled during the deceleration
v = 0 m/s ....the car's final velocity is 0 because it stops.
u = 20 m/s ......the car's initial velocity is 20 m/s
t = 3 s
Calculate the distance travelled
S = t(u+v)/2
S = 3( 20 + 0)/2
S = 60/2
S = 30 meters
The distance travelled is
The total distance travelled is:
25 metres + 100 metres + 30 metres
= 155 metres
Answer:
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