A car starts from rest and moves along the x-axis with constant acceleration 6 m sâ2 for 10 seconds. If it then continues with constant velocity, what distance will the car cover in 15 seconds since it started from rest ?
(1) 180 m
(2) 300 m
(3) 320 m
(4) 420 m
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Here is your Answer :-
a= 6m/s^2
t = 10 seconds
u = 0
v = u+at
v = 0+6*10 = 60m/s
For first 10 seconds :-
s=ut + at^2/2
s= 0 + 6*100/2
s = 600/2 = 300 metres
So, for first 10 seconds the car travels 300m.
For last 5 seconds,
v = s/t
60 = s/5
60*5 = s
s = 300 metres
According to me, the answer should be (300+300)= 600m
a= 6m/s^2
t = 10 seconds
u = 0
v = u+at
v = 0+6*10 = 60m/s
For first 10 seconds :-
s=ut + at^2/2
s= 0 + 6*100/2
s = 600/2 = 300 metres
So, for first 10 seconds the car travels 300m.
For last 5 seconds,
v = s/t
60 = s/5
60*5 = s
s = 300 metres
According to me, the answer should be (300+300)= 600m
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