A car traveling at 36km/hr speeds up to 70km/hr in 5 seconds. What is its acceleration? If
the same car stops in 20s, what is the retardation?
Answers
Answered by
130
hello friend
pls find ur answer below
first case ( when the car accelerates )
given, u= 36km/hr = 10m/s
v = 70km/hr = 20m/s
t= 5 sec.
a =?
we know that a = v-u/t
so a = ( 20-10) / 5
a= 10/5
a= 2m/s²
second case ( when car retards )
given,
u= 20m/s
t= 20 sec.
v= 0m/s
a=?
using first equation of motion, we get
= v = u + at
= 0 = 20 + 20a
= - 20 = 20a
= -1 m/s²
so the retardation of car is -1m/s²
hope this clears all ur doubts ..
pls find ur answer below
first case ( when the car accelerates )
given, u= 36km/hr = 10m/s
v = 70km/hr = 20m/s
t= 5 sec.
a =?
we know that a = v-u/t
so a = ( 20-10) / 5
a= 10/5
a= 2m/s²
second case ( when car retards )
given,
u= 20m/s
t= 20 sec.
v= 0m/s
a=?
using first equation of motion, we get
= v = u + at
= 0 = 20 + 20a
= - 20 = 20a
= -1 m/s²
so the retardation of car is -1m/s²
hope this clears all ur doubts ..
armaanmalik285:
pls mark it as brainliest answer
Answered by
81
A car traveling at 36 km/hr speeds up to 70 km/hr in 5 seconds. What is its acceleration? If the same car stops in 20 s, what is the retardation?
Initial velocity = u = 36km/hr = 36 x 5/18 = 10 m/s
Final velocity = v = 70 km/hr = 70 x 5/18 = 19.4 m/s
Time = t = 5 sec
acceleration = a = v - u /t
= 19.4-10/5
= 1.88 m/s²
=============================
t = 20 sec
Initial velocity = u = 19.4 m/s
Final velocity = v = 0 m/s
acceleration = 0-19.4/20
= -0.97 m/s²
Hence ,
the retardation = -0.97 m/s²
Initial velocity = u = 36km/hr = 36 x 5/18 = 10 m/s
Final velocity = v = 70 km/hr = 70 x 5/18 = 19.4 m/s
Time = t = 5 sec
acceleration = a = v - u /t
= 19.4-10/5
= 1.88 m/s²
=============================
t = 20 sec
Initial velocity = u = 19.4 m/s
Final velocity = v = 0 m/s
acceleration = 0-19.4/20
= -0.97 m/s²
Hence ,
the retardation = -0.97 m/s²
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