A car travelling at 36km/hr to 72km/hr in 5 sec.what is it's acceleration
Answers
Answered by
1
We have
u=36 km/h
v=72 km/h
t=5/60 h [we have to change all into same unit]
a=v-u/t
a=72-36/t
a=36/t
a=36×60/5=2160/5=432 km/hr^2
u=36 km/h
v=72 km/h
t=5/60 h [we have to change all into same unit]
a=v-u/t
a=72-36/t
a=36/t
a=36×60/5=2160/5=432 km/hr^2
Answered by
1
hey here is ur answer....
here...
initial speed, u= 36km/h = 10m/s
final speed, v = 72 km/h = 20m/s
now...
from relation v=u + at ...we have
a =(v-u) / t
. = (20 - 10) / 5
. = 10/5
a= 2m/s²
hope this helps in a better way..plz mark it brainliest.
here...
initial speed, u= 36km/h = 10m/s
final speed, v = 72 km/h = 20m/s
now...
from relation v=u + at ...we have
a =(v-u) / t
. = (20 - 10) / 5
. = 10/5
a= 2m/s²
hope this helps in a better way..plz mark it brainliest.
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