Find the zeroes of the polynomial P(x) = (x – 2 )^2 – ( x+2)^2
Answers
Answered by
6
Hi friend,
p(x) = (x-2)² - (x+2)²
{a²-b² = (a+b)(a-b)}
(x-2+x+2)(x-2-(x+2)) = 0
(2x)(x-2-x-2) = 0
(2x)(-4) = 0
-8x = 0
x = 0/-8
x = 0
Therefore,the zero of the given polynomial is 0.
Hope it helps
p(x) = (x-2)² - (x+2)²
{a²-b² = (a+b)(a-b)}
(x-2+x+2)(x-2-(x+2)) = 0
(2x)(x-2-x-2) = 0
(2x)(-4) = 0
-8x = 0
x = 0/-8
x = 0
Therefore,the zero of the given polynomial is 0.
Hope it helps
Answered by
0
Answer:
yes x=0 is the correct answer
Step-by-step explanation:
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